All friends are nice except cma.

f(x)=ax^2+bx+c ,if we have 3 indepent conditions,we can decide  a,b,c and get anser.5 is ff's repeat root,2 is f's root,3 conditionss,so we got answer. But cma did not say yes, so I thoght again.3-2=1,our answer should have a parametric variablee.following is my best for cma:

f(x)=a(x-2)(x-p),p is not a real number,(15less is right,he likes saying white horse is not horse)

ff(x)=a^3((x-2)(x-P)-2/a)(x-2)(x-p)-p/a),ff(5)=a^3(3(5-p)-2/a)(3(5-p)-p/a))=0 we get

p=15a/(3a+1) or p=5a-2/3. f(0)=30a^2/(3a+1) or -2a(5a-2/3).a can take any number except p being real number.In fact a can't be real number and some special complex singular points.