P(-A)=1-p,P(-B)=1-p,P((-A))(-B))=(1-p)(1-p)=P(-A)P(-B),so,(-A)

來源: jinjing 於 2011-02-04 13:49:18 [舊帖] [給我悄悄話] 本文已被閱讀：次

定義就是您的J成立.

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P(-A)=1-p,P(-B)=1-p,P((-A))*(-B))=(1-p)(1-p)=P(-A)*P(-B),so,(-A)