I try for infinite n

來源: 2010-10-22 10:00:25 [舊帖] [給我悄悄話] 本文已被閱讀:

P(notE)=1/2^2+1/3^2+1/5^2+...

        -1/2^2*1/3^2-1/2^2*1/5^2-...

        +1/2^2*1/3^2*1/5^2+....

        -........

P(E)=1-P(notE),the limit, I quess ,is open question.