Sorry,First term is not right.

來源: 於 2010-09-13 17:47:58 [舊帖] [給我悄悄話] 本文已被閱讀：次

（a1+b1x）（a2+b2x）......（an+bnx）={b1[（b2+c3b3+c4...+cnbn)a1/b1-（b2+c3b3+...cnbn）x]（a2+b2x）（c3a3+c3b3x）...（cnan+cnbnx）}/c3c4...cn（b2+c3b3+...cnbn）....We get n equations,but only n-1 is independent.We can get x.