x^2y^2+(x^2-1)^2=R^2y^2, y can't be 0

來源: jinjing 於 2010-04-23 16:09:19 [舊帖] [給我悄悄話] 本文已被閱讀：次

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x^2*y^2+(x^2-1)^2=R^2*y^2, y can't be 0