不考慮a=0,這樣ab就不是兩位數了。 a0b can only be ab x 9 if such exist (a, b !=0 -> ab x 10 > a0b, ab x 8 ok: 100a + b = 9 x (10a + b) 10a = 8b a:b = 4:5 the only digits satisfy this is a=4, b=5 405/45 =9, so 45 is the only solution.