m>n f(m) - f(n) = 1/n sum_{1 f(2n) > f(n) since p(x+y) This will prove 1 consider another case, n is a sufficiently large prime, m = p + 1 since in this p(m/k) = p(m/k) + p(1/k) when k f(p+1) this will prove 2